[Torg] Jumping in Torg
Sam Frazier II
sdf_ii at yahoo.com
Wed Dec 10 20:13:02 EST 2008
I love the math. Looks great. Now translate that into TORG math and you got a winner. Otherwise...well too complicated. I'll import my car-wars game as the charts are already there with no calculators needed.
Keep up the good work.
SDF II
-----------------------------
So now we have three answers:
A) to find the total distance assuming that you land at the *same* level you
took off from:
RAMP INCLINE SCN
5 or 85 degrees use 0.09
10 or 80 degrees use 0.17
15 or 75 degrees use 0.25
20 or 70 degrees use 0.32
25 or 65 degrees use 0.38
30 or 60 degrees use 0.43
35 or 55 degrees use 0.47
40 or 50 degrees use 0.49
45 degrees use 0.5
Simply look up the degree of the ramp or incline above to plug in to the
formula:
(.2) times (Speed in m/s, squared) times (SCN factor from table) = total
horizontal distance
B) To find the total max height of the jump, use the quick cheat sheet
below:
RAMP INCLINE RIF (Ramp Incline Factor = Sin(N))
5 degrees use 0.09
10 degrees use 0.17
15 degrees use 0.26
20 degrees use 0.34
25 degrees use 0.42
30 degrees use 0.50
35 degrees use 0.57
40 degrees use 0.64
45 degrees use 0.71
50 degrees use 0.77
55 degrees use 0.82
60 degrees use 0.87
65 degrees use 0.91
70 degrees use 0.94
75 degrees use 0.97
80 degrees use 0.98
85+degrees use 1.00
... and use the formula: [(S*RIF)^2]/2 to get max jump height from liftoff
point.
Make sure that S, your ramp speed, is in meters/second. If you are using a
ramp, add H, the ramp height to get the total height of jump.
C) And finally, to find the total complete distance jumped when taking off
at a higher level than you land, including the small bit extra, use:
0.1 * S*Cos(N) * [ [20H+([S*Sin(N)]^2)]^.5 + S*Sin(N) ]
Where S = ramp speed in m/s, H = ramp height in meters, N = ramp incline -
sorry, there is no cheat sheet for this one.
Enjoy.
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